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So I have the cost Matrix[N][N] and 2 arrays to track covered rows and covered cols - row Cover[N], row Column[N] (1 means covered, 0 means uncovered) How can I cover the 0s with the minimum number of lines? This method was very similar to the one I independently implemented and tested (before looking in stackoverflow for an alternate solution! Try this one netlib.org/utk/lsi/pcw LSI/text/[email protected] Wyss-Gallifent sorry for the delay to answer, I've made some adjustments to the algorithm, basically added a heuristic to keep searching for rows or columns with the same direction of the last line pushed.
Min num of lines for example matrix is: 3 Before: 0 1 0 0 5 1 0 3 4 5 7 0 0 4 5 9 0 3 4 5 3 0 3 4 5 After: - - - - 1 | 3 4 5 - - - - 9 | 3 4 5 3 | 3 4 5 Min num of lines for example matrix is: 4 Before: 0 0 1 0 0 1 1 0 1 1 0 0 1 0 0 0 After: | | | | | | | | | | | | | | | | Min num of lines for example matrix is: 6 Before: 0 0 0 0 0 0 0 0 0 1 0 0 0 0 1 1 0 0 0 1 1 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 After: - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - Your code will first choose column 4 (with four zeros) but then perhaps the next line it chooses is row 1 (with two remaining zeros) followed by row 4 (with two remaining zeros) and then row 2 (with one remaining zero) followed by row 3 (with one remaining zero) giving a total of five [email protected] Wyss-Gallifent is right.
Here's a brief explanation on how my algorithm for this step works: The advantage of having those 3 methods is that we know the elements that are covered twice, we know which elements are covered, and which are not covered.
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